A British Werewolf in South Park

Jan 9, 19984 posts by 3 postersalt.tv.southpark
4 posts

After seeing "An American Werewolf in Paris" and "An American Werewolf in London" I think it would be cool for a Halloween South Park episode where Pip is a werewolf. It could be called "A British Werewolf in South Park" and Kenny dies of (how else?) a werewolf attack. It would be the goriest Kenny death EVER! Kenny would get ripped to shreds! Just remember, if Trey and Matt see this, they might make it into an episode. So you can say you heard it here first on alt.tv.southpark! ��� �hr�B

"Engelbert Humperdink was the first man on the moon who was the second?" -- Mr. Hat

���th ��rk R�Lɧ because it does!

www.geocities.com/CapitolHill/Senate/1479 Pip's Pipperific Page!

G�T �H�ʧ� ��؃�������

[email] (NOA ChrisB) wrote:

	According to myths, not all people die from werewolf attacks.
Many people are turned into werewolves themselves.  If Kenny *did* get
mauled, then he could go around South Park and either kill people, or
make more werewolves.
	Oh, and also the person who kills the main werewolf (Pip) will
turn into a werewolf (supposedly, anyways).  So whoever kills Pip
would be a werewolf.  It'd be kinda funny to see Cartman kill Pip,
then the next time there's a full moon, he goes on top of his roof and
yells, "I WANT CHEESY POOOOOOOOOOOFS!"

X

To discover is to conquer

Naah... that would be too similar to Pink Eye. We don't want SP to turn into the same episodes w/ slightly different characters, now would we?

See ya dude, Richard Hunt

Well, you know how "The Simpsons" has an annual Halloween episode? Well the same thing could be for South Park!

Oh. It would be cool if Chef killed the werewolf Then there'd be a sweet-lovin' werewolf!

HAHAHAHAHA!!!

Uhh, excuse me? Pink Eye had zombies. This is WAY different

Maybe, maybe not!

��� �hr�B

"Engelbert Humperdink was the first man on the moon who was the second?" -- Mr. Hat

���th ��rk R�Lɧ because it does!

www.geocities.com/CapitolHill/Senate/1479 Pip's Pipperific Page!

G�T �H�ʧ� ��؃�������